One root of f(x) = 2x3 + 9x2 + 7x – 6 is –3. explain how to find the factors of the polynomial.


Asked by maham237 @ in Mathematics viewed by 526 People

Answered by maham237 @



We have the following polynomial:

f(x)=2x^{3}+9x^{2}+7x-6

The problem states that one root is -3. Thus, it is true that (x+3) is a factor of the polynomial. Given that this is fulfilled, it is also true that:

f(x)=(x+3)Q(x) \therefore Q(x)=\frac{f(x)}{x+3} \\ \\ where \ Q(x) \ has \ a \ degree \ of \ 2

We can find Q(x) by applying Ruffini's rule, thus:

\ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ 9 \ \ \ \ \ \ \ \ 7 \ \ \ \ \ \ -6  \\ -3 \\ \rule{50mm}{0.1mm} \\ \ {} \ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ 3 \ \ \ \ \ -2 \ \ \ \ \ \ \ \ 0

Therefore:


Q(x)=2x^{2}+3x-2


The roots of this polynomial can be get as follows:

x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \rightarrow x_{12}=\frac{-3\pm\sqrt{3^2-4(2)(-2)}}{2(2)}\\x_{1}=\frac{1}{2};\ x_{2}=-2


These are the roots along with -3. Finally, the factored polynomial can be written as follows:


f(x)=(x+3)(x+2)(2x-1)

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