Find the roots of 2x 2 7x 3 0
Asked by admin @ in Math viewed by 310 People
Find the roots of the equation 2x^2-7x+3=0 by completing the square method
Answered by admin @
2x^2-7x=-3
X^2-7x/2=-3/2
X^2-2x1/2x7x/2=-3/2
X^2-2x1/2x7x/2+(7/4)^2=-3/2+(7/4)^2
(X-7/4)^2=-3/2+49/16
(X-7/4)^2=25/16
X-7/4=+or -5/4
x=+5/4+7/4
X=12/4=3
Also
X=-5/4+7/4
2/4=1/2
Hence x=3 and 1/2
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