1 x 3 1 2x 1 11 7x 9


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1/x+3+1/2x-1 =11/7x+9

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To solve for x from the equation with fractions ?

\frac{1}{x+3}+\frac{1}{2x-1}=\frac{11}{7x+9}\\\\\frac{2x-1+x+3}{2x^2+5x-3}=\frac{11}{7x+9}\\\\21 x^2+41x+18=22x^2+55x-33\\\\x^2+14x-51=0\\\\(x-3)(x+17)=0\\\\x=3\ or\ -17

x = 3 or -17


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