If f(x) = log3 (x + 1), what is f−1(2)?


Asked by maham237 @ in Mathematics viewed by 310 People


1
8
10
27

Answered by maham237 @



Answer:

Option B. 8

Step-by-step explanation:

Given function is f(x)=log_{3}(x + 1)

Now we have to find the value of f^{-1}(x).

Since f(x)= y=log_{3}(x+1)

3^{y}=(x + 1)

Now for f^{-1}(x)

we will replace x by y.

3^{x}=y + 1

y=3^{x}-1

f^{-1}(x)=3^{x}-1

Now we put the value of x = 2

y = 3²- 1 = 9-1 = 8

Therefore f^{-1}(2)=8 is the answer.


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