Y 1 xy dx x 1 xy dy 0
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Slove y(1/xy) dx+x(1-xy)dy=0
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Answer:
– (1/xy) = log |(y/x)| + c
Step-by-step explanation: (1 + xy)ydx + x(1 – xy)dy = 0
ydx + xdy + xy(ydx – xdy) = 0 d(xy) + xy(ydx – xdy) = 0
(d(xy)/(xy)) + (ydx – xdy) = 0 d(xy)/(xy) = (xdy – ydx)
d(xy)/(xy)2 = (xdy – ydx)/xy = (dy/y) – (dx/x)
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