The magnitude of average acceleration in half time period


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The magnitude of average acceleration is half time period for equilibrium position is a simple harmonic motion is

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average acceleration of particle is \frac{2\omega^2A}{\pi}

the magnitude of average acceleration in half the time period for an simple harmonic motion is ....

standard equation of particle moving in SHM, x = Asinωt

after double differentiation we get,

d²x/dt² = a = -ω²Asinωt

for getting average acceleration during 0 to T/2

so, a_{av}=\frac{\int\limits^{T/2}_0{a(t)}\,dt}{\int\limits^{T/2}_0dt}

= -\omega^2A\frac{\int\limits^{T/2}_0{sin\omega t}\,dt}{T/2}

= -\frac{2\omega^2A}{T}\left[\frac{-cos\omega t}{\omega}\right]^{T/2}_0

as T = 2π/ω then, T/2= π/ω

= \frac{4\omega^2 A}{2\pi}

= \frac{2\omega^2A}{\pi}

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