Pipe a can fill a tank in 20 minutes

Asked by admin @ 16/08/2021 in Math viewed by 317 People

Pipe A can fill in 20 minutes and Pipe B in 30 mins and Pipe C can empty the same in 40 mins.If all of them work together, find the time taken to fill the tank

(a) 17 1/7 mins
(b) 20 mins
(c) 8 mins
(d) none of these

Answered by admin @ 16/08/2021

Answer:

$17\frac{1}{7}$ minutes

Step-by-step explanation:

Pipe A can fill in 20 minutes

Pipe A can do work in 1 minute = $\frac{1}{20}$

Pipe B can fill in 30 mins

Pipe B can do work in 1 minute = $\frac{1}{30}$

Pipe C can empty the same in 40 mins

Pipe C can do work in 1 minute = $\frac{1}{40}$

So, they can do work together in 1 minute = $\frac{1}{20}+\frac{1}{30}-\frac{1}{40}$

= $\frac{7}{120}$

They can fill $\frac{7}{120}$ part in minutes = 1

They can fill full tank in minutes = $\frac{1}{\frac{7}{120}}$

= $17\frac{1}{7}$

Hence the time taken to fill the tank is $17\frac{1}{7}$ minutes

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