Pipe a can fill a tank in 6 hours


Asked by admin @ in Math viewed by 291 People


Pipe a can fill a cistern in 6 hours and pipe b can fill it in 8 hours. Both the pipes are opened and after two hours. Pipe a is closed. How much time will b take to fill the remaining part of the tank

Answered by admin @



Answer:

3 hours 20 mins


Step-by-step explanation:

Pipe A can fill the cistern in 6 hours

1 hour = 1/6 of the cistern


Pipe B can find the cistern in 8 hours

1 hour = 1/8 of the cistern


If both worked together

1 hour = 1/6 + 1/8 = 7/24 of the cistern

2 hours = 7/24 x 2 = 7/12 of the cistern


Find amount of work left after 2 hours

work left = 1 - 7/12 = 5/12 of the cistern


Find the amount of time needed for B to finish the rest of the work:

1 hour = 1/8 of the cistern

Number of hours needed = 5/12 ÷ 1/8 = 3 1/3 hours

3 1/3 hours =  3 hours 20 mins


Answer: It will take 3 hours 20 mins for Pipe B to fill the remaining of the tank.


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