If o is the center of the circle find


Asked by admin @ in Math viewed by 432 People


If O is the centre of the circle, find the value of x in each of the following figures :

Answered by admin @



Given:  O is the center of the circle.

 

To find : The value of x .

 

Solution :  

(i) From figure : ∠AOC = 135° , ∠COB = x

∴ ∠AOC + ∠BOC = 180°

[Linear pair]

135° + ∠BOC = 180°

∠BOC = 45°

 

Since, the angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.

∴ ∠BOC = 2 ∠COB

45° = 2x

x = 45°/2

x = 22½°

Hence x is 22½°
.  

(ii) From figure : ∠ABC = 40° , ∠CDB = x

We know that angle in semi-circle is 90°.

∠ACB = 90°  

In ∆ ABC,  

Since Sum of the angles of a triangle is 180° :  

∴ ∠CAB + ∠ACB + ∠ABC = 180°

∠CAB + 90° + 40° = 180°

∠CAB + 130° = 180°

∠CAB  = 180° - 130°  

∠CAB = 50°

Now,

Since angles in the same segment of a circle are equal :

∴ ∠CDB = ∠CAB  

x = 50°

Hence x is 50°.

 

(iii) From figure : ∠AOC = 120° , ∠CBD = x  

Since, the angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.

∠AOC = 2 ∠APC

120° = 2 ∠APC

∠APC = 120°/2

∠APC = 60°

Since, APCB is a cyclic quadrilateral, and Sum of Opposite pair of angles in a  cyclic quadrilateral is 180° :  

∴ ∠APC + ∠ABC = 180°

60° + ∠ABC = 180°

∠ABC = 180° - 60°

∠ABC = 120°

 

∠ABC + ∠DBC = 180°

[Linear pair]

120° + x = 180°

x = 180° - 120°

x = 60°

Hence x is 60°.

HOPE THIS ANSWER WILL HELP YOU…..

 

Similar questions :

In Fig. 16.120, O is the centre of the circle. If ∠APB=50°, find ∠AOB and ∠OAB.

brainly.in/question/15910134

 

In Fig. 16.122, O is the centre of the circle. Find ∠BAC.

brainly.in/question/15910117


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