What is the general form of the equation for the given circle centered at o(0, 0)?.

Asked by maham237 @ in Mathematics viewed by 469 People

What is the general form of the equation for the given circle centered at O(0, 0)?
a) x2 + y2 + 41 = 0
b) x2 + y2 − 41 = 0
c) x2 + y2 − 41 = 0
d) x2 + y2 + x − y − 41 = 0

Answered by maham237 @



hello :
an equation of the circle Center at the
O(a,b) and ridus : r is :

(x-a)² +(y-b)² = r²

in this exercice : a =0 and b = 0 (Center at the origin)

r = AO

r² = (AO)²

r² = (4-0)² +(5-0)² = 16+25=41

an equation of the circle that satisfies the stated conditions.

Center at the origin, passing through B(4, 5) is : x² +y² = 41

x² +y² - 41=0


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