Abcd is a rhombus whose diagonals intersect at o
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ABCD is a rhombus whose diagonals intersect at O show that angle AOB equal to angle C O D
Answered by admin @
We know that , diagonals of rhombus bisect each other.
So, OA = OC and OB = OD [given]
In triangle AOB and triangle COD
AO = OC [ GIVEN ]
∠AOB = ∠COD [ VERTICALLY OPPOSITE ANGLES]
BO = OD [ GIVEN ]
So, triangle AOB is congruent to triangle COD [ SAS ]
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