The vapour pressure of a dilute solution of glucose

Asked by admin @ 23/08/2021 in Chemistry viewed by 497 People

the vapour pressure of a dilute aqueous solution of glucose is 750 mm of mercury at 373 k. the mole fraction of solute is:

Answered by admin @ 23/08/2021

Given in the question :-

Temperature = 373 Kvapour pressure H2O , p°= 760 mm
$p^s$ = 750 mm

From the Rault law

$(p^0-p^s)/p^0$

Now mole fraction of the solute
Put the values in the formula
$(p^0-p^s)/p^0$

$\frac{760-750}{760}$
$10/760$
0.013

Hence the mole fraction is 0.013

Hope it Helps :-)

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