The vapour pressure of an aqueous solution of sucrose

Asked by admin @ 20/08/2021 in Chemistry viewed by 491 People

The vapour pressure of an aqueous solution of sucrose at 373k is found to be 750mm hg. the molality at same temperature is

Answered by admin @ 20/08/2021

Given that

pressure at 373 of solution is 750 mm Hg.

Pressure of solvent means water at 373 K is 760 mmHg

According to the Raoult’s law;

Psoln = PH2O XH2O

750 = 760 (XH2O)

mole fraction; XH2O = 0.987

mole fraction = moles of water / total number of moles (water + solute )

Here mass of water is 1.00 kg or 1000 g

Therefore;

Number of moles = amount in g / molar mass

= 1000g 18.02 g/ mole= 55.6 moles H2O,

And from mole frcation;

0.987 = 55.6 /(55.6 + x)

x = moles glucose = 0.777 moles

and molality = moles solute / kg solvent, molality = 0.777 m

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