How many photons are contained in a flash of green light (525 nm) that contains 189 kj of energy?

Asked by maham237 @ 15/12/2020 in Chemistry viewed by 397 People

Answered by maham237 @ 15/12/2020

Answer: 4.99×10²³ photons

Explanation: The energy of a photon is given as

E= hf

h= Planck constant = 6.626×10^-34Js

f= frequency = c/x

C= speed of light = 3×10^8 m/s

x= wavelength= 525nm= 525×10^-9

E= hc/x

E= 6.626×10^-34 × 3×10^8 m/s /( 525×10^-9)

E= 3.79×10^−19 J/ Photon

E= 3.79×10^−22KJ/Photon

189KJ/3.79×10^−22KJ/photon=

4.99×10²³photons.

Therefore the number of photons is

4.99×10²³photons.

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