Calculate the approximate enthalpy change , δh∘, for the combustion of methane: ch4+2o2⇌2h2o+co2

Asked by maham237 @ in Chemistry viewed by 471 People

ΔHrxn from a given table:
CH4 = 1656 kJ/mol
O2 = 498 kJ/mol
H2O = 928 kJ/mol
CO2 = 1598 kJ/mol
ΔHrxn = [(1656) + (2*498)] - [(2*928) + (1598)] = -802 kJ/mol ?

Answered by maham237 @


The heat of combustion is obtained by getting the difference between the summation of enthalpies of the products and the enthalpies of the reactants. Hence the equation is enthalpy change= 1598 kJ+2*928 kJ-1656 kJ-498 kJ. The answer is 1300 kJ.

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