Given standard enthalpy of formation of co and co2


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Given standard enthalpy of formation of co (-110 kj mol) co2 (-394 kj mol) the heat of combustion when one mole graphite burns

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Answer : The heat of combustion when one mole graphite burns is, -394 kJ

Explanation :

Standard formation of reaction : It is a chemical reaction that forms one mole of a substance from its constituent elements in their standard states.

The balanced chemical equation for the standard formation reaction of gaseous carbon monoxide will be,

C(graphite)+\frac{1}{2}O_2(g)\rightarrow CO(g)  (incomplete combustion)

The standard enthalpy of CO = -110 kJ/mol

The balanced chemical equation for the standard formation reaction of gaseous carbon dioxide will be,

C(graphite)+O_2(g)\rightarrow CO_2(g)   (complete combustion)

The standard enthalpy of CO_2 = -394 kJ/mol

The complete combustion of carbon graphite gives carbon dioxide as a product.

So, the heat of combustion when one mole graphite burns is, -394 kJ.


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