2 mole of an ideal gas at 27 c

Asked by admin @ 17/08/2021 in Chemistry viewed by 335 People

2 mole of an ideal gas at 27°C expands isothermally and reversibly from a volume of 4 litre of 40 litre. The work done (in KJ) by the gas is:

Answered by admin @ 17/08/2021

Answer: 11.49 kJ

Explanation: Work done by a an ideal gas isothermally:

$w=-2.303nRTlog\frac{V_2}{V_1}$

n = no of moles = 2

R = gas constant= 8.314J/Kmol

T= temperature = 27°C = 27+273= 300 K

$V_2$ = final volume = 40 L

$V_1$ = initial volume = 4 L

$w=-2.303\times 2mol\times 8.314J/Kmol\times 300Klog\frac{40L}{4L}$

w = 11,488.3J = 11.49kJ

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