Two ends of a train moving with constant acceleration

Asked by admin @ 20/08/2021 in Physics viewed by 333 People

The two ends of a train moving with constant acceleration pass a certain point with velocities u and 3u. The velocity with which the middle point of the train passes the same point is

Answered by admin @ 20/08/2021

S = (v^2 - u^2) / (2a)

If Length of train is L then
L = ((3u)^2 - u^2) / (2a)
L = 4u^2 / a —-(1)

Midpoint is at Distance L/2
S = (v^2 - u^2) / (2a)
L/2 = (v^2 - u^2) / (2a)
From equation (1)
2u^2 / a = (v^2 - u^2) / (2a)
4u^2 = v^2 - u^2
v^2 = 5u^2
v = u√5

Velocity with which middle point passes the same point is u√5.

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Two ends of a train moving with constant acceleration

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