Two capacitors c1 and c2 are connected in series

Asked by admin @ 17/08/2021 in Physics viewed by 278 People

two capacitors C1 and C2 are connected in series. if potential at A is V1 and at B is V2,the potential atD is

Answered by admin @ 17/08/2021

Answer:

Explanation:

Secondary School Physics 5+3 pts

Two capacitors C1 and C2 are charged to potential V1 and V2 resp. and then connected in parallel. Calculate common potential, charge on each capacitor and energy in the system after connection??

Report by Rush8192 18.01.2019

Answers

gadakhsanket

Gadakhsanket★ Brainly Teacher ★

Hello Buddy,

◆ Answer -

¶ V = (C1V1+C2V2)/(C1+C2)

¶ Q1 = C1(C1V1+C2V2)/(C1+C2)

¶ Q2 = C2(C1V1+C2V2)/(C1+C2)

¶ E = (C1V1+C2V2)^2 /2(C1+C2)

◆ Explaination -

When capacitors are separated, total charge on capacitors

Qi = C1V1 + C2V2

When capacitors are connected in parallel with voltage V, total charge is

Qf = (C1+C2)V

By law of conservation of momentum,

Qi = Qf

C1V1 + C2V2 = (C1+C2)V

V = (C1V1+C2V2)/(C1+C2)

Charge on capacitor 1 is -

Q1 = C1V

Q1 = C1(C1V1+C2V2)/(C1+C2)

Charge on capacitor 2 is -

Q2 = C2V

Q2 = C2(C1V1+C2V2)/(C1+C2)

Energy in the system is calculated by-

E = 1/2 (C1+C2)V^2

E = (C1V1+C2V2)^2 /2(C1+C2)

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