Two balls are projected simultaneously with the same speed

Asked by admin @ 13/08/2021 in Physics viewed by 304 People

Two balls are projected simultaneously with

the same speed from the top of a tower, onevertically upwards and the other verticallydownwards. They reach the ground is 9 s and 4s, respectively. The height of the tower is (g =10 m/s)

Answered by admin @ 13/08/2021

Answer:

180 m

Explanation:

Two balls are projected simultaneously with

the same speed from the top of a tower, one

vertically upwards and the other vertically

downwards. They reach the ground is 9 s and 4

s, respectively. The height of the tower is (g =

10 m/s)

Let say Velocity = V

Using S = ut + (1/2)at²

Height of Tower = Distance Covered in 4 Sec = V*4 + (1/2)(10)4²

= 4V + 80

Another take time to reach ground = 9 sec

Time taken to come back at projected point = 9 - 4 = 5 sec

Time to reach peak height = 5/2 sec

Velocity at peak height = 0

=> 0 = V - 10*5/2

=> V = 25

Height of Tower = 4V + 80 = 4*25 + 80 = 180 m

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