The velocity at the maximum height of a projectile

Asked by admin @ 23/08/2021 in Physics viewed by 291 People

The velocity at the maximum height of a projectile is half of its initial velocity of projection u. Its range on the horizontal plane is

Answered by admin @ 23/08/2021

At maximum height
velocity = uCosθ
u/2 = uCosθ
θ = 60°

R = u² Sin(2θ) / g
= u² Sin(2 × 60°) / g
= u²√3 / (2g)

Range on horizontal plane is u²√3 / (2g)

The maximum height reached by a projectile is 4m

Asked by admin @ 17/08/2021 in Physics viewed by 320 persons

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Asked by maham237 @ 27/12/2020 in Physics viewed by 336 persons

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Asked by wiki @ 09/11/2020 in Physics viewed by 664 persons

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