The maximum kinetic energy of the photoelectrons gets doubled

Asked by admin @ 23/08/2021 in Physics viewed by 300 People

The maximum kinetic energy of the photoelectrons gets doubled when the wavelength of light incident on the surface changes from 1 to 2. establish a relation for threshold wavelength th in terms of 1 and 2?

Answered by admin @ 23/08/2021

AnswEr :-

Einstein's photoelectric equation states,

$\sf {h\nu=W_0 +KE}$

Where,

$\sf {\nu - Frequency\ of\ incident\ light}\\\\\sf {W_0 - Work\ potential\ of\ the\ metal}\\\\\sf {KE - Maximum\ kinetic\ energy\ of\ released\ electron}$

From given data,

$\sf {\frac{hc}{\lambda_1} = KE + W_o}\\\\\sf {\frac{hc}{\lambda_2} = 2KE + W_o}\\\\$

Eliminating KE, work function is given by:

$\sf {W_o = \frac{2hc}{\lambda_1} - \frac{hc}{\lambda_2}}$

Threshold wavelength is found by:

$\sf {\frac{hc}{\lambda_o} = W_o}$

Using above equations,

$\sf {\lambda_o = \frac{\lambda_1\lambda_2}{2\lambda_2-\lambda_1} }$

$\rule {130}{2}\ Be\ Brainly\ \star$

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