Impedance of the circuit shown in the figure is
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Impedance of the circuit shown in the figure is
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impedance of the circuit shown in the figure is
Voltage across resistance
V = IR
90 = 3 * R
=> R = 30 Ω
Voltage across inductor
V = I XL
120 = 3 * XL
XL = 40 Ω
Impedance Z = R + jXL
Magnitude if impedance = √(R² + XL²)
= √(30² + 40²)
= √(900 + 1600)
=√2500
= 50 Ω
Option2
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