Find component of a 2i 3j along b 3i 4j

Asked by admin @ 03/08/2021 in Physics viewed by 285 People

Find component of A=2i+3j along B=3i+4j

Answered by admin @ 03/08/2021

A = 2i + 3j
B = 3i + 4j

|A| = √(2² + 3²) = √(13)
|B| = √(3² + 4²) = 5

A · B = |A||B| cosθ
|A| cosθ = [ A · B ] / |B|
= [ 6 + 12 ] / 5
= 18 / 5
= 3.6

Component of A along B is 3.6

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