Electric field intensity calculator

Asked by maham237 @ 18/02/2021 in Physics viewed by 369 People

Calculate the electric field intensity at a point 3 cm away from point charge of
3 x 10^-9 C. SHOW YOUR WORK

Answered by maham237 @ 18/02/2021

The intensity of the electric field is 30 000 N/C

Explanation:

The magnitude of the electric field produced by a single-point charge is given by:

$F=k\frac{q}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q$ is the magnitude of the charge

r is distance from the charge

In this problem, we have:

$q=3\cdot 10^{-9}C$ is the magnitude of the charge

r = 3 cm = 0.03 m is the distance from the charge

Substituting into the equation, we find the intensity of the field:

$E=(8.99\cdot 10^9) \frac{3\cdot 10^{-9}}{0.03^2}=30,000 N/C$

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