Derivation of kinetic energy and potential energy class 9
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Derivation of kinetic energy class 9
Answered by admin @
Let the body of mass M kg is moving with velocity V M / s
work done to stop body equals kinetic energy of the body
from third equation of motion
v²=u²+2as
a=v²-u²/2s
here u = 0
a=v²/2s.. ............(i)
work done = FS
= m x a x s......... .....( F =m x a)
from equation 1
kinetic energy =mxv²/2sxs
= mv²/2
hence kinetic energy = mv²/2
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