An object 2cm high is placed at a distance


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an object 2cm high is placed at a distance of 16cm from a concave mirror which produces a real image 3cm high.      what is focal length of the mirror and position of the image??????

Answered by admin @



Height of the object, h1 = 2 cm
height of the image, h2 = -3 cm
object distance, u = -16cm
image distance = v

magnification =  \frac{h2}{h1} = \frac{-v}{u}
 
 \frac{-3}{2} = \frac{-v}{-16}

(-16)*(-3)=2*(-v)
v = - \frac{48}{2} =-24cm

From mirror formula 
 \frac{1}{u} + \frac{1}{v} = \frac{1}{f}  \\  \\  \frac{1}{-16} + \frac{1}{-24} = \frac{1}{f} \\  \\  \frac{3+2}{-48} = \frac{1}{f} \\  \\  \frac{5}{-48} = \frac{1}{f} \\  \\ f= \frac{-48}{5} = -9.6cm

So focal length is 9.6cm and image distance is 24cm(to the left of mirror)

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