An elevator carrying a maximum load of 1800 kg

Asked by admin @ 23/08/2021 in Physics viewed by 391 People

An elevator can carry a maximum load of 1800kg, is moving up with a constant speed of 2m/s. The frictional force opposing the motion is 4000N. Determine the minimum power delivered by the motor to the elevator in watts. (take g=9.8m/s 2

Answered by admin @ 23/08/2021

Elevator moves upward hence frictional force oppose their motion in downward.
so, net force act on elevator =mg+F
because mg is act downward and F (frictional force) act also downward.
Fnet=(1800 x 9.8+4000) N
=(17640+4000)N=21640N
now
power =Fnet x speed
=21640 x 2=43280 watt

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