A vertical straight conductor carries a current vertically upward

Asked by admin @ 17/08/2021 in Physics viewed by 326 People

A vertical straight conductor carries a current vertically upwards. A point P lies to the east of it at a small distance and another point Q lies to the west at the same distance. The magnetic field at P is

(EXPLAIN) a) Greater than that at Qb) Same as at Qc) Less than at Qd) Greater or less than at Q depending upon strength of current

Answered by admin @ 17/08/2021

$\mathfrak{ \huge{ \red{ \underline{ \underline{Answer}}}}} \\ \\ \boxed{ \blue{ B = \frac{ \mu \: I}{4 \pi \: x} ( \sin( \theta1) + \sin( \theta2)) }}$

=> Magnetic field at a point which is situated at x distance from straight wire is given by this formula...

=> Here, distance between wire and P point and distance between wire and Q point is same = x

=> Also, angle at P and Q point is same...

=> So, magnetic field at both point is same in magnitude but not same in direction...

=> At P point direction of magnetic field is inside and at Q point direction is Outside...

$\boxed{\bold{\huge{ \star}}} \: \: \boxed{ \boxed{ \pink{magnetic \: field \: at \: P \: point = magnetic \: field \: at \: Q \: point}}} \: \: \boxed{\huge{ \bold{ \star}}}$

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