A sailboat moves north for a distance of 10.00 km

Asked by maham237 @ 23/05/2021 in Physics viewed by 377 People

when blown by a wind from the exact southeast with a force of 2.00 × 104 N. The sailboat travels the distance in 1.0 h. How much work was done by the wind? What was the wind’s power? Your response should include all of your work and a free-body diagram.

Answered by maham237 @ 23/05/2021

Answer: The work done by the boat is $2\times 10^8 Joules$ .

The power of the wind is $5.55\times 10^4 watts$ .

Explanation:

Force of the wind in the boat = $2.00\times 10^4 N$

Displacement of the boat = 10 km = 10,000 m

Work done = Force × Displacement =

$2\times 10^4 N\times 10,000 m=2\times 10^8 Joules$

Duration of time for which boat sailed = 1 hour

Power of the wind = $\frac{Energy}{Time}$

= $\frac{2\times 10^8 Joules}{1\times 60\times 60 seconds}=5.55\times 10^4 watts$

The work done by the boat is $2\times 10^8 Joules$ .

The power of the wind is $5.55\times 10^4 watts$ .

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