A metal ball of radius r is placed concentrically

Asked by admin @ 17/08/2021 in Physics viewed by 364 People

A metal ball of radius `r` is placed concentrically inside hollow metal sphere of inner radius `2r` and outer radius `3r`.The ball is given a charge `+2q` and the hollow sphere a total charge `-q` .The electrostatic potential energy of this system is

Answered by admin @ 17/08/2021

The electrostatic potential energy of this system is V = 7Q^2 / 24πϵ0 R

Explanation:

Radius =R=R

Inner radius =2R=2R

Outer radius =3R=3R

Charge =+2Q=+2Q

Hollow sphere a total charge = −Q

The electrostatic potential energy of this system=

By indication, inner wall of hollow sphere is induced with share −2.Q and its outer surface with charge.

Two conducting concentric, hollow sphere AA and BB have radii a and b respectively.

V = 1/4πϵ0 ×
Q/R

when, it is given that,

V^1 = 1 / 4 4πϵ0 x 2Q /2R

V^11 = 1 / 4πϵ0 x Q /3R

V = Q / 4πϵ0 x (2Q / 2R + Q / 3R)

V = 1 / 4πϵ0 x 6 Q +2Q / 6R

V = 7Q^2 / 24πϵ0 R

Thus the electrostatic potential energy of this system is V = 7Q^2 / 24πϵ0 R

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A metal ball of radius r is placed concentrically

The electrostatic potential energy of this system is V = 7Q^2 / 24πϵ0 R

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