A grindstone has a moment of inertia of 6


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A grindstone has a moment of inertia of 6 kg m2. A constant torque is applied and the grindstone is

found to have a speed of 150 rpm. 10 seconds after starting from rest. Calculate the torque.​

Answered by admin @



Answer:

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Explanation:

Given that,

Time t=10s

Speed ω=150rpm=150×602π=5πr/s

Moment of inertia I=6kgm2

Now, the angular acceleration is

  α=tω

 α=105π

 α=2π

Now, the torque is

  τ=Iα

 τ=6×2π

 τ=3πNm

Hence, the torque is 3πNmGiven that,

Time t=10s

Speed ω=150rpm=150×602π=5πr/s

Moment of inertia I=6kgm2

Now, the angular acceleration is

  α=tω

 α=105π

 α=2π

Now, the torque is

  τ=Iα

 τ=6×2π

 τ=3πNm

Hence, the torque is 3πNm

If the moment of inertia of the grindstone is 6 kgm^2 the torque is: ... is found to have a speed of 150 rpm, 10 seconds after starting from rest .


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