A given wire of resistance 1 ohm is stretched


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A given wire of resistance 1 ohm is stretched to double its length what will be the new resistance

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R=ρ \frac{l}{a}

New length = 2l

New area of cross section = a/2

Therefore new resistance R' = ρ \frac{2l}{a/2}

                                             = 4R

∴ R' = 4R


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