A galvanometer together with an unknown resistance in series

Asked by admin @ 20/08/2021 in Physics viewed by 257 People

A galvanometer together with an unknown resistance in series is connected across two identical batteries each of 1.5 volts when the batteries are connected in series the galvanometer records a current of 1 m and when batteries are connected in parallel the current is 16 and what is the internal resistance of each battery

Answered by admin @ 20/08/2021

Answer:

Explanation:

The net resistance = R+2r

Potential Difference(V) = 3V

As from the ohms law

3 = 1(R+2r)---------- 1.)

The net resistance in second case = R+r/2

V = 1.5V I =6A

1.5 = 6(R+r/2)

¼ =R+r/2 ---------(2.)

3r/2 = 11/4

r = 22/12

r =1.83 ohm

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