A ball is thrown vertically upward with velocity u


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a ball is thrown vertically upward with a velocity u from the top of a tower. If it strikes the ground with velocity 3u the time taken by the ball to reach the ground is

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Here we make use of the formula  v=u+at , here  v final velocity,  u initial velocity,  a acceleration ( in the direction of velocity is taken as positive) and  t time taken.

The time taken by the ball to reach the top most point (when the velocity becomes 0) is given by

 u-gt_1=0\\ t_1=\frac{u}{g}

The time taken to reach a velocity  3u from an initial velocity of 0 is

 3u=0+gt_2\\ t_2=\frac{3u}{g}

The time taken by the ball to reach the ground, after throwing from the top of the tower is
 t=t_1+t_2\\ t=\frac{u}{g}+\frac{3u}{g} \\ t=\frac{4u}{g}


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