A 5 kg collar is attached to a spring

Asked by admin @ in Physics viewed by 276 People

A 5kg collar is attached to a spring of force constant 500n/m it slides without friction on a horizontal rod the collar is displaced from its equilibrium position by 10.0cm and released calculate the period of oscillation the maximum speed and the maximum acceleration of the collar

Answered by admin @


m = 5kg

k = 500 Nm^ -1

A = 10 cm = 0.01 m

T = 2 π √ m/k = 2 x 3.14 √ 5 / 500 = 0.6284 s

v_m = A = A √ k / m = 0.1 √ 500 / 5 = 1 ms^-1

a_max = k / m x A = 500 / 5 x 0. 1 = 10 ms^-2


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