Which student miscalculated her average

Asked by maham237 @ 12/01/2021 in Mathematics viewed by 343 People

Students collected data about the capacities of their lungs by inflating balloons with a single breath. they measured the circumference of the balloons in centimeters. each student completed three trials and calculated the average. balloon circumference (cm) student trial 1 trial 2 trial 3 average 1 66.0 66.5 68.5 67.0 2 67.5 64.0 70.5 67.3 3 60.3 60.5 60.5 61.0 4 55.0 58.0 59.0 57.3 which student miscalculated her average? 1. student 1 2. student 2 3. student 3 4. student 4

Answered by maham237 @ 12/01/2021

The given data is the following:

Student Trial 1 Trial 2 Trial 3 Average
----------- -------- -------- -------- ------------
1 66.0 66.5 68.5 67.0
2 67.5 64.0 70.5 67.3
3 60.3 60.5 60.5 61.0
4 55.0 58.0 59.0 57.3

Let us check the reported averages.
Student 1:
Average = (66.0 + 66.5 + 68.5)/3 = 67.0 Correct
Student 2:
Average = (67.5 + 64.0 + 70.5)/3 = 67.3 Correct
Student 3:
Average = (60.3 + 60.5 + 60.5)/3 = 604 Incorrect
Student 4:
Average = (55.0 + 58.0 + 59.0)/3 = 57.3 Correct

Answer: Student 3

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