What is the factored form of 6n4 24n3 18n


Asked by maham237 @ in Mathematics viewed by 484 People


What is the factored form of 6n4 – 24n3 + 18n?

Answered by maham237 @



Answer: Its factored form will be

6n(n-1)(n^2-3n-3)

Step-by-step explanation:

Since we have given that

6n^4-24n^3+18n

So, we need to factor ,

6n(n^3-4n^2+3)

Now,

\text{Let }p(n)=n^3-4n^2+3

Now, by hit and trial method, we put n=1,

p(1)=1^3-4\times1^2+3=1-4+3=1-1=0

n=1\\n-1=0

So, n-1 is also factor of p(n).

Now,

\frac{n^3-4n^2+3}{n-1}=n^2-3n-3

So, its factored form will be

6n(n-1)(n^2-3n-3)


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