What is the f of x over the g of x when f(x) = − 2x3 + x2 + 16x − 15 and g(x) = x + 3?

Asked by maham237 @ 23/12/2020 in Mathematics viewed by 343 People

What is the f of x over the g of x when f(x) = − 2x3 + x2 + 16x − 15 and g(x) = x + 3?
−2x2 − 5x + 1
− 2x2 + 7x − 5
−2x2 + 7x − 5 − 12 over the quantity of x plus 3
− 2x2 − 5x + 1 − 12 over the quantity of x plus 3

Answered by maham237 @ 23/12/2020

− 2x3 + x2 + 16x − 15 and g(x) = x + 3. Find f(x) / g(x).
One way to do this is to use synthetic division. Given the divisor (x+3), we decide that the divisor in synth. div. is -3. Then:

__________________
-3 / -2 +1 16 -15
6 -21 15
-----------------------------
-2 7 -5 0

Because there's no remainder, we can conclude that -3 is a root of the given function and (x+3) is a factor. The coefficients of the quotient are

{-2, 7, -5), which works out to -2x^2 + 7x - 5.

Kindly use the symbol " ^ " for exponentiation: x^2 Right
x2 Wrong

What is the f of x over the g of x when f(x) = − 2x3 + x2 + 16x − 15 and g(x) = x + 3?

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