What is the arc length if θ = 6 pi over 5 and the radius is 2 cm?
Asked by maham237 @ in Mathematics viewed by 346 People
Answered by maham237 @
The arc length :
L = r π (theta) / π = r *(theta) = 2 · 6 π / 5 = 12π / 5
( 12 · 3.14 ) : 5 = 7.536
Answer: 7.536 cm.
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