Unit 1 geometry basics homework 3 distance and midpoint formulas

Asked by maham237 @ in Mathematics viewed by 375 People

Unit 1: Geometry Basics
Date:
Per: Homework 3: Distance & Midpoint Formulas
** This is a 2-page document! **
Directions: Find the distance between each pair of points.
1. 1-4.6) and (3.-7)
2. (-6,-5) and (2.0)
M=(-12,-1)
M=
4. (0.-8) and (3.2)
3. (-1, 4) and (1-1)
5.
.
Directions: Find the coordinates of the midpoint of the segment given its endpoints.
6. /15, 8) and B(-1,-4)
7. M(-5,9) and N[-2.7)
8. P(-3,-7) and Q13.-5)
9. F12.-6) and G(-8,5)
Gina Whion (All Things Algobro. LLC) 2014-2017

Answered by maham237 @


Answer:

The answer is below

Step-by-step explanation:

The distance between two points is given by the formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2)}

1) (-4,6) and (3, -7)

D=\sqrt{(3-(-4))^2+(-7-6)^2}=14.76

2) (-6, -5) and (2,0)

D=\sqrt{(2-(-6))^2+(0-(-5))^2}=9.43

3) (0, -8) and (3, 2)

D=\sqrt{(3-0)^2+(2-(-8))^2}=10.44

4) (-1, 4) and (1, -1)

D=\sqrt{(1-(-1))^2+(-1-4)^2}=5.39

The midpoint (x, y) between two endpoints is given by:

x=\frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}

The midpoints of the following segments are:

1) (15, 8) and (-1, -4)

x=\frac{15+(-1)}{2}=7,y=\frac{8+(-4)}{2}=2\\\\(7,2)

2) M(-5,9) and N[-2.7)

x=\frac{-2+(-5)}{2}=-3.5,y=\frac{7+9}{2}=8\\\\(-3.5,8)

3) P(-3,-7) and Q13.-5)

x=\frac{-3+13}{2}=5,y=\frac{-7-5}{2}=6\\\\(5,6)

4) F(12.-6) and G(-8,5)

x=\frac{12+(-8)}{2}=2,y=\frac{-6+5}{2}=0.5\\\\(2,0.5)


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