The lengths of the sides of a right triangle are a and b, and the hypotenuse is c. find the area of the triangle. b = 2 in.; c = 6 in. a = sq. in.


Asked by maham237 @ in Mathematics viewed by 324 People

Answered by maham237 @



Answer:

\sqrt{32}sq. in

Step-by-step explanation:

To find the area of a triangle, we need to know the base and perpendicular to the base (height) of the triangle.

For a right triangle,

(Hypotenuse)² = (Base)² + (Perpendicular)²

We can find the perpendicular first from the above relation.

Given, Hypotenuse, c = 6 in

Base, b = 2 in

Perpendicular, a = \sqrt{c^2-b^2} = \sqrt {6^2-2^2}=\sqrt{36-4}=\sqrt{32}

The area of triangle:

A = \frac{1}{2}{b}{a} = \frac{1}{2}\times 2 \times \sqrt{32} =\sqrt{32}sq. in.


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