The direction of the magnetic force on the proton is

Asked by admin @ 16/11/2021 in Mathematics viewed by 252 People

What is the magnetic force on a proton that is moving at 2.5 x 10 m/s to the

left through a magnetic field that is 3.4 T and pointing toward you? The
charge on a proton is 1.6 10-19 c. Use F-qvx B sin(o).

Answered by admin @ 16/11/2021

Answer:C. 1.4 10-11 N up

step-by-step explanation:

Explanation:

The magnetic force, F on a charge q moving with velocity v in a magnetic field B at an angle θ is given by:

F = q v B sin θ

Charge of proton, q = 1.6 × 10⁻¹⁹ C

Strength of magnetic field, B = 3.4 T pointing outwards

velocity of the proton, v = 2.5 × 10⁷ m/s towards left

Magnetic force is given by:

F = 1.6 × 10⁻¹⁹ C× 2.5 × 10⁷ m/s ×3.4 T× sin 90 = 13.6 × 10⁻¹² N = 1.4 × 10⁻¹¹ N up

The direction of the force is given by Lorentz Right hand rule. The fingers point magnetic field, the thumb points towards velocity, then the force on the proton is given by the direction perpendicular to the palm.

The magnetic field acts outwards with velocity of the proton towards left. The force would act perpendicular to the two -upwards.

The direction of the magnetic force on the proton is

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