Prove diagonals of parallelogram bisect each other
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Prove that the diagonals of a parallelogram bisect each other.
The midpoint of AC is
Answered by maham237 @
Answer:
Theorem: The diagonals of a parallelogram bisect each other. Proof: Given ABCD, let the diagonals AC and BD intersect at E, we must prove that AE ∼ = CE and BE ∼ = DE. The converse is also true: If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.
Step-by-step explanation:
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