How to find instantaneous rate of change from an equation

Asked by admin @ 26/11/2021 in Mathematics viewed by 282 People

100 POINTS AND BRAINLIEST ANSWER

What is the instantaneous rate of change of the function f(x) = 6x^2 - x at the point (-1,7)
a. -13
b. -5
c. 7
d. 11
What is the equation of the line tangent to the function f(x) = -x^2 + 5 at the point (1,4)
a. y = -x + 5
b. y = -x + 9
c. y = -2x + 6
d. y = -2x + 9

Answered by admin @ 26/11/2021

Answer:

Just took the test,

1)d, 3

2)a, -13

3) c, y=-2x+6

4) c, f'(a)=8a+2

Step-by-step explanation:

For #3, graph f(x)=-x^2+5. Next graph y=-2x+6. You will see that the added equation touches at exactly the point (1,4). this make it the tangent line equation

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