How many solutions does this linear system have? y = 2x – 5 –8x – 4y = –20

Asked by maham237 @ 02/12/2020 in Mathematics viewed by 364 People

How many solutions does this linear system have?
y = 2x – 5

–8x – 4y = –20

a. one solution: (–2.5, 0)
b. one solution: (2.5, 0)
c. no solution
d. infinite number of solutions

Answered by maham237 @ 02/12/2020

If you would like to solve the system of equations, you can do this using the following steps:

y = 2x - 5
-8x - 4y = -20
___________
-8x - 4y = -20
-8x - 4 * (2x - 5) = -20
-8x - 8x + 20 = -20
20 + 20 = 16x
16x = 40
x = 40/16
x = 2.5

y = 2x - 5 = 2 * 2.5 - 5 = 5 - 5 = 0

(x, y) = (2.5, 0)

The correct result would be: b. one solution: (2.5, 0).

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