Given right triangle jkl, what is the value of cos(l)?


Asked by wiki @ in Mathematics viewed by 532 People


A. 5/13
B. 5/12
C. 12/13
D. 12/5

Answered by wiki @


Step 1

In the right triangle JKL

Find the value of JL

Applying the Pythagorean Theorem

JL^{2} =JK^{2}+KL^{2}

in this problem we have

JK=12\ units\\KL=5\ units

substitute the values

JL^{2} =12^{2}+5^{2}

JL^{2} =169

JL=13\ units

Step 2

Find the value of cos(L)

we know that

cos(L)=\frac{adjacent\ side\ angle\ L}{hypotenuse}=\frac{KL}{JL}=\frac{5}{13}

therefore

the answer is the option A

cos(L)=\frac{5}{13}


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