Find the value of x round to the nearest degree

Asked by maham237 @ 23/05/2021 in Mathematics viewed by 245 People

Answered by maham237 @ 23/05/2021

Answer:

$\large\boxed{x=51}$

Step-by-step explanation:

Use sine:

$sine=\dfrac{opposite}{hypotenuse}$

We have:

$opposite=7\\\\hypotenuse=9$

Substitute:

$\sin x^o=\dfrac{7}{9}\\\\\sin x^o=0.777...\\\\\sin x\approx0.7778\to x\approx51^o$

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