Find the fifth roots of 32(cos 280° + i sin 280°).


Asked by maham237 @ in Mathematics viewed by 426 People


I have gotten to the point where I have 2(cos(128) + isin(128)) but I don't know where to go from there.

Answered by maham237 @



Use the formula: r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ] where k = 0,1,2,3,4

First 5th root:
k = 0

r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ]

(32)^(1/5)*[ cos( (280+360*k)/5 ) + i*sin( (280+360*k)/5 ) ]

(32)^(1/5)*[ cos( (280+360*0)/5 ) + i*sin( (280+360*0)/5 ) ]
2*[ cos( (280+360*0)/5 ) + i*sin( (280+360*0)/5 ) ]

2*[ cos( (280+0)/5 ) + i*sin( (280+0)/5 ) ]

2*[ cos( 280/5 ) + i*sin( 280/5 ) ]

2*[ cos( 56 ) + i*sin( 56 ) ]

-------------------------------------------------------------------

Second 5th root:
k = 1

r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ]

(32)^(1/5)*[ cos( (280+360*k)/5 ) + i*sin( (280+360*k)/5 ) ]

(32)^(1/5)*[ cos( (280+360*1)/5 ) + i*sin( (280+360*1)/5 ) ]

2*[ cos( (280+360*1)/5 ) + i*sin( (280+360*1)/5 ) ]

2*[ cos( (280+360)/5 ) + i*sin( (280+360)/5 ) ]

2*[ cos( 640/5 ) + i*sin( 640/5 ) ]

2*[ cos( 128 ) + i*sin( 128 ) ]
-------------------------------------------------------------------

Third 5th root:
k = 2

r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ]

(32)^(1/5)*[ cos( (280+360*k)/5 ) + i*sin( (280+360*k)/5 ) ]

(32)^(1/5)*[ cos( (280+360*2)/5 ) + i*sin( (280+360*2)/5 ) ]

2*[ cos( (280+360*2)/5 ) + i*sin( (280+360*2)/5 ) ]
2*[ cos( (280+720)/5 ) + i*sin( (280+720)/5 ) ]

2*[ cos( 1000/5 ) + i*sin( 1000/5 ) ]

2*[ cos( 200 ) + i*sin( 200 ) ]

-------------------------------------------------------------------

Fourth 5th root:
k = 3

r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ]

(32)^(1/5)*[ cos( (280+360*k)/5 ) + i*sin( (280+360*k)/5 ) ]

(32)^(1/5)*[ cos( (280+360*3)/5 ) + i*sin( (280+360*3)/5 ) ]

2*[ cos( (280+360*3)/5 ) + i*sin( (280+360*3)/5 ) ]

2*[ cos( (280+1080)/5 ) + i*sin( (280+1080)/5 ) ]

2*[ cos( 1360/5 ) + i*sin( 1360/5 ) ]

2*[ cos( 272 ) + i*sin( 272 ) ]
-------------------------------------------------------------------

Fifth 5th root:
k = 4

r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ]

(32)^(1/5)*[ cos( (280+360*k)/5 ) + i*sin( (280+360*k)/5 ) ]

(32)^(1/5)*[ cos( (280+360*4)/5 ) + i*sin( (280+360*4)/5 ) ]

2*[ cos( (280+360*4)/5 ) + i*sin( (280+360*4)/5 ) ]

2*[ cos( (280+1440)/5 ) + i*sin( (280+1440)/5 ) ]

2*[ cos( 1720/5 ) + i*sin( 1720/5 ) ]

2*[ cos( 344 ) + i*sin( 344 ) ]


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