1 2 practice points lines and planes form k answers


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Name:

Unit 1 Test Study Guide
(Geometry Basics)
Date:
Per:
M
Topic 1: Points, Lines & Planes
Use the diagram to the right to answer questions 1-4.
1. Name two points collinear to point K.
2. Give another name for line b.
3. Name the intersection of line c and plane R.
4. Name a point non-coplanar plane R.
H
b
Use the diagram to the right to answer questions 5-8.
5. How many planes are shown in the figure
6. Give another name for plane W.
7. Name the intersection of plane ADE and plane W.
8. Name a point non-collinear to points A and B.
A
Oy
Topic 2: Segment Addition Postulate
9. If DF = 42, find DE.
7x + 1 4x-3
10. In the diagram below, if JL = 10x - 2.
JK = 5x - 8, and KL = 7x - 12. find KL.

Answered by admin @



From the given diagrams given, the following answers can be deduced:

1. J, L

2. HK

3. K

4. N

5. 2 planes

6. A B C D

7. AD

8. E

9. DE = 29

10. KL = 51

Points, lines and planes are important properties of geometry. So that the following are the answers to the questions.

a. For the first part of the question:

1. Collinear points are two or more points that can be connected by a straight line.

So that; point J and point L are collinear to K.

2. HK

3. K

4. Point N

b. For the second part of the question:

5. 2 planes

6. A B C D

7. Intersection here implies the meeting point of plane W and ADE. So that the answer is AD

8. Non- collinear points are points that can not be joined by a straight line. The required point is E.

c. For segement addition postulate:

9. Given that: DF = 42, DE = 7x + 1, and EF = 4x - 3. Then;

DF = DE + EF

42 = (7x + 1) + (4x - 3)

    = 11x - 2

11x = 42 + 2

11x = 44

x = 4

So that;

DE = (7x + 1)

     = (7(4) + 1)

DE = 29

10. Given that; JL = 10x - 2, JK = 5x - 8, and KL = 7x - 12.

But,

JL = JK + KL

(10x - 2) = (5x - 8) + (7x - 12)

10x - 2 = 12x - 20

collecting like terms;

20 - 2 = 12x - 10x

18 = 2x

x = 9

Then;

KL = (7x - 12)

     = (7(9) - 12)

KL = 51

More information: brainly.com/question/17524573


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